- 满足条件的数累加
第三方
- @ 2025-3-14 16:10:18
5 条评论
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胡诗瑶 LV 6 @ 2025-12-29 16:59:52#include <iostream> #include <iomanip> using namespace std; int main(){ int m,n,s=0; cin>>m>>n; if(m%17!=0){ m=(m/17+1)*17;} for(;m<=n;m+=17) { s=s+m; } cout<<s; return 0; }❤️ 1😄 1👍 1 -
@ 2025-12-17 16:55:36
了
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@ 2025-11-17 17:25:03
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@ 2025-11-17 16:55:35
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@ 2025-8-7 8:37:19答案哪?
- 1
信息
- ID
- 70
- 时间
- ms
- 内存
- MiB
- 难度
- 2
- 标签
- 递交数
- 90
- 已通过
- 56
- 上传者