- 判断一个数能否同时被3和5整除
key
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赵洲 LV 8 @ 2025-7-17 14:33:09
#include<iostream>
using namespace std;
int main(){
int a;
cin>>a;
if(a%15==0){
cout<<"YES";
}
else{
cout<<"NO";
}
return 0;
}
1 条评论
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吕梓锐 LV 7 @ 2025-9-19 15:59:52已修改答案
#include <bits/stdc++.h>
using namespace std; int main(){ int n; cin >> n; if(n%3==0 && n%5==0){ cout << "YES"; } else cout << "NO"; return 0; }🤡 2
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