挺简单的，一个三目运算符就KO了

#include<bits/stdc++.h>
using namespace std;
#define int long long
char a;
signed main(){
    cin>>a;
    cout<<(signed(a)%2?"YES":"NO");
    return 0;
}

#include using namespace std; int main ( ){ char a; int b; cin>>a; b=(int)(a); if(b%2==1) cout<<"YES"; else cout<<"NO"; return 0; }

#include<bits/stdc++.h>
using namespace std;
int main(){
	char n;
	cin>>n;
    int(a);
	if(n%2!=0){
		cout<<"YES";
	}	
	else if(n%2==0){
		cout<<"NO";
	}				
	return 0;
}

#include<bits/stdc++.h>
using namespace std;
char n;
int m;
int main(){
    cin >> n;
    m=n;
    m=m%2;
    if(m==1)
    cout<<"YES";
    if(m==0)
    cout<<"NO";
    return 0;
}

#include<bits/stdc++.h> using namespace std; int main(){ char a; cin>>a; a=int(a); if(a%21) { cout<<"YES"; } if(a%20) { cout<<"NO"; } return 0; }