11 条题解

  • 1
    @ 2026-4-18 14:35:21

    C++:

    #include<bits/stdc++.h>
    using namespace std;
    int a,b,c,d,e,f,g,h,i,j;
    int main(){ 
    	cin>>a>>b>>c>>d>>e>>f>>g>>h>>i>>j;
       cout<<278-a-b-c-d-e-f-g-h-i-j; 
       return 0;
    }
    

    最简单的,求赞,谢谢!

    • 0
      @ 2025-12-14 20:28:30

      666

      #include<bits/stdc++.h>
      #define int long long
      using namespace std;
      signed main() 
      {
      	int sum=0;
      	for(int i=1;i<=10;i++)
      	{
      		int t;
      		cin>>t;
      		sum+=t;
      	}
      	cout<<278-sum;
      }
      
      • 0
        @ 2025-11-30 12:18:30
        ```cpp
        #include <iostream>
        #include <cstdio>
        using namespace std;
        const int  MAXN = 11;
        int ans[MAXN],sum;
        int main(){
            int a = 278;
            for (int i = 1;i <= 10;i++)    {
                cin >> ans[i];
                sum+=ans[i];
            }
            printf("%d",a-sum);
            return 0;
        }
        
        • 0
          @ 2025-11-23 8:41:18
          #include<bits/stdc++.h>
          using namespace std;
          int main()
          {
          	int ans=0;
          	for(int i=1;i<=10;i++)
          	{
          		int s;
          		cin>>s;
          		ans+=s;
          	}
          	cout<<278-ans; 
          	return 0;
          } 
          
          
          • -1
            @ 2025-8-4 11:11:01

            肥肠水的一道题目:

            #include<iostream> 
            #define QwQ return 0;
            using namespace std;
            int total;
            int main(){
            	for(int i=1;i<=10;i++){
            		int x;cin>>x;
            		total+=x;
            	}
            	cout<<278-total;
            	QwQ
            }
            
            • -1
              @ 2025-6-15 11:17:52
              #include<bits/stdc++.h>
              #define int long long
              using namespace std;
              signed main() 
              {
              	int sum=0;
              	for(int i=1;i<=10;i++)
              	{
              		int t;
              		cin>>t;
              		sum+=t;
              	}
              	cout<<278-sum;
              }
              
              • -1
                @ 2025-5-25 18:02:31

                #include<bits/stdc++.h> using namespace std; int main(){ int q,w,e,r,t,y,u,i,o,p,a; cin>>q>>w>>e>>r>>t>>y>>u>>i>>o>>p; a=(278-q-w-e-r-t-y-u-i-o-p); cout<<a; return 0; }

                • -1
                  @ 2024-12-28 11:22:32
                  #include<bits/stdc++.h>
                  using namespace std;
                  int n,ans;
                  signed main(){
                  	for(int i=1;i<=10;i++){
                  		cin>>n;
                  		ans+=n;
                  	}
                  	cout<<278-ans;
                  }
                  
                  • @ 2025-5-25 18:02:22

                    没必要这么复杂吧! 看看我的: #include<bits/stdc++.h> using namespace std; int main(){ int q,w,e,r,t,y,u,i,o,p,a; cin>>q>>w>>e>>r>>t>>y>>u>>i>>o>>p; a=(278-q-w-e-r-t-y-u-i-o-p); cout<<a; return 0; }

                • -1
                  @ 2024-12-27 21:20:15

                  虽然比李宥锦多了两行,但是还是比较容易实现的。题目太水了。

                  #include<bits/stdc++.h>
                  #define int long long
                  #define INF 0x3f3f3f
                  using namespace std;
                  int x,ans;
                  signed main(){
                  	for(int i=1;i<=10;i++)
                  		cin>>x,ans+=x;
                  	cout<<278-ans;
                  	return 0;
                  }
                  
                  • @ 2025-8-3 21:02:52

                    其实第2,3行可以不加,加不加没关系

                    #define int long long #define INF 0x3f3f3f

                • -1
                  @ 2024-12-23 21:36:41

                  暴力打法:

                  #include<bits/stdc++.h>
                  using namespace std;
                  int main()
                  {
                  	int a,b,c,d,e,f,g,h,i,j;
                  	cin>>a>>b>>c>>d>>e>>f>>g>>h>>i>>j;
                  	cout<<278-a-b-c-d-e-f-g-h-i-j;
                  	return 0;
                  }
                  

                  你懂的,它要几个班我开几个变量(就是头铁~ 怎么滴~)。

                  • -1
                    @ 2024-12-22 11:03:53

                    C++ :

                    #include <bits/stdc++.h>
                    using namespace std;
                    int n,s=0;
                    int main(){
                    	for(int i=1;i<=10;i++){
                    		cin>>n;
                    		s+=n;
                    	}
                    	cout<<278-s;
                    	return 0;
                    }
                    

                    Python :

                    # coding=utf-8
                    a, b, c, d, e, f, g, h, i, j = input().split()
                    a = int (a)
                    b = int (b)
                    c = int (c)
                    d = int (d)
                    e = int (e)
                    f = int (f)
                    g = int (g)
                    h = int (h)
                    i = int (i)
                    j = int (j)
                    x = (a + b + c + d + e + f + g + h + i + j)
                    n = x
                    print (278 - n)
                    
                    • 1

                    信息

                    ID
                    13
                    时间
                    1000ms
                    内存
                    128MiB
                    难度
                    1
                    标签
                    递交数
                    385
                    已通过
                    400
                    上传者